풀이
삼성 인사 담당자님 보고 계신가요?
코드
#include <cstdio>
#include <vector>
#include <algorithm>
using namespace std;
const int dx[] = { 0,1,0,-1 }, dy[] = { 1,0,-1,0 };
const int R = 1, D = 2, L = 4, U = 8;
vector<int> sight[6] = { {},
{ R,D,L,U },
{ L+R,U+D },
{ R+D,D+L,L+U,U+R },
{ R+D+L,D+L+U,L+U+R,U+R+D },
{ R+D+L+U }
};
int n, m;
int a[10][10], b[10][10];
struct abc { int x, y; };
vector<abc> cam;
inline void paint(int x, int y, int dir, int dif) {
b[x][y] += dif;
while (a[x][y] != 6) {
x += dx[dir], y += dy[dir];
b[x][y] += dif;
}
}
int gogo(int cnum) {
int x = cam[cnum].x, y = cam[cnum].y;
int cdir = a[x][y];
if (cnum == cam.size()) {
int cnt = 0;
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= m; j++) {
if (!b[i][j]) cnt++;
}
}
return cnt;
}
int ret = 1e9;
for (int sgt : sight[cdir]) {
for (int i = 0; i < 4; i++) {
if (sgt & (1<<i)) paint(x, y, i, +1);
}
ret = min(ret, gogo(cnum+1));
for (int i = 0; i < 4; i++) {
if (sgt & (1<<i)) paint(x, y, i, -1);
}
}
return ret;
}
int main() {
scanf("%d %d", &n, &m);
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= m; j++) {
scanf("%d", &a[i][j]);
if (1 <= a[i][j] && a[i][j] <= 5) cam.push_back({ i,j });
if (a[i][j] == 6) b[i][j] = 1;
}
}
for (int i = 0; i <= n+1; i++) a[i][0] = a[i][m+1] = 6;
for (int i = 0; i <= m+1; i++) a[0][i] = a[n+1][i] = 6;
printf("%d", gogo(0));
return 0;
}
아무말
백준, 백준 온라인 저지, BOJ, Baekjoon Online Judge, C, C++, 씨, 씨쁠쁠, JAVA, algorithm, 자바, 알고리즘, 자료구조, 문제, 문제 풀이, 풀이